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Parse command line and some utility functions

Posted on | August 9, 2007 |

I was assigned to write a dictionary module for a huge MFC project. The library as well as the executable has to be fully compliance with standard c++.

Now, I have to write a parser. I know I don’t really have to write one, as there is already many out in the net. Why to make the wheel again ? Well known answer — as I can :)

//Declare
wstring CLGetKeyValue(wstring cl ,wstring key, wstring::size_type pos=0);
void ParseCommandLine(wstring cl,wstring::size_type pos=0);

std::map <wstring,wstring> tb;


//this is for parsing

void ParseCommandLine(wstring cl,wstring::size_type pos)

{

wstring::size_type p1 = cl.find(L“-”,pos);

if((int)p1

return;

wstring::size_type p2 = cl.find(L” -”,p1+1);

if((int)p2

p2 = cl.length();

wstring pair = cl.substr(p1,(p2-p1));

int mid = (int)pair.find(L” “);

tb.insert(make_pair(pair.substr(1,mid-1),pair.substr(mid+1,pair.length()))) ;

ParseCommandLine(cl,p2);

}

//This checks the presence of a key

inline int CLHasKey(wstring cl,wstring key)

{

if((int)cl.find(L“-”+key+L” “)

return 0;

return 1;

}

//It returns the key value, assumed that the key is present

wstring CLGetKeyValue(wstring cl, wstring key, wstring::size_type pos)

{

//should be checked CLHasKey(cl,key);

wstring::size_type p1 = cl.find(L“-”,pos);

if((int)p1

return L“”;

wstring::size_type p2 = cl.find(L” -”,p1+1);

if((int)p2

p2 = cl.length();

wstring pair = cl.substr(p1,(p2-p1));

int mid = (int)pair.find(L” “);

if( key.compare(pair.substr(1,mid-1)) ==0 )

{

return pair.substr(mid+1,pair.length());

}

return CLGetKeyValue(cl,key,p2);

}

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Comments

2 Responses to “Parse command line and some utility functions”

  1. Eddie
    April 6th, 2008 @ 11:14 am

    stop saying grose things about this! It’s your terrible way of thinking! Normal people don’t care about stuff like that

  2. Bruno Ribeiro
    April 9th, 2008 @ 2:27 am

    Very well! Are you dudes agree with me? When I read it I was like: oh man!Sounds great! This is just what I was searching for! All is true, and checked, I’m sure.

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